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« With 4.5m votes in, election could be half over in FL. A look at the white, black and brown early vote | Main | Voting in Florida off to a smooth start, Detzner says »
The computer model of the New York Times statistics guru, Nate Silver of the Five Thirty Eight blog, indicates President Obama has a 52 percent chance of winning Florida, without which Mitt Romney can't win the presidency.
Basically, it's a coin toss election. And already, up to half of the vote is in. More here on that.
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It is odd, I think that Florida only matters to Romney. As if he loses Florida; he has no chance of winning the Presidency. I do though predict; a very serious problem in many counties.I think it will take weeks to determine who actually wins our 29 electorol votes. Once again, I believe Floriduh; will go to the Supreme Court of the United States. This time, though; a prescident(unlike the last time) must be set. otherwise, it all comes down to who has the most money, and who is willing to pay for the office.
Posted by: naplesbob | November 06, 2012 at 08:34 AM
Today is the day of everything :)
Posted by: John | November 06, 2012 at 10:01 AM
Even with Scotts attempts at votet suppression, it shows Obama ahead...What an arrogant ass!
Posted by: kerry | November 06, 2012 at 10:06 AM
A flawed analysis. Each election cycle is different. In 2012---the D early voting turnout is down 5%. Moreover, the undecided and independent vote has gone to Romney by a 2-1 margin. Finally, the Republican turnout is far better than it was in 2008--and even then McCain won Florida on votes cast on electio day. The bottom line: Romney has a 75% chance of winning Florida.
Posted by: HSamuels | November 06, 2012 at 10:08 AM